je découvre Arch linux et je n'ai peut-être pas les bons réflexes....
je me suis inspiré de ce site :
http://blog.programmableproduction.com/ ... th-Netctl/
Voila mon problème :
J'ai 2 cartes réseaux Ethernet
- carte ethernet carte mère (enp0s10)
- Adaptateur USB /Ethernet ( enp0s4flu2)
Au démarrage de l'ordinateur s'affiche :
[Failed] Failed to start A basic Static Ethernet connection.
J'ai créé 2 fichiers sous /etc/netctl:[test@archlinux netctl]$ ifconfig
enp0s10: flags=4163<UP,BROADCAST,RUNNING,MULTICAST> mtu 1500
inet 192.168.0.90 netmask 255.255.255.0 broadcast 192.168.0.255
inet6 2a01:e0a:2b7:c450:6ef:25e:60ff:eef prefixlen 64 scopeid 0x0<global>
inet6 fe80:af8:eb46:b652 prefixlen 64 scopeid 0x20<link>
ether 00:01:6c:6d:a5:df txqueuelen 1000 (Ethernet)
RX packets 1883 bytes 266876 (260.6 KiB)
RX errors 0 dropped 0 overruns 0 frame 0
TX packets 1073 bytes 118390 (115.6 KiB)
TX errors 0 dropped 0 overruns 0 carrier 0 collisions 0
enp0s4f1u2: flags=4163<UP,BROADCAST,RUNNING,MULTICAST> mtu 1500
inet6 fe80::404612f3:a970 prefixlen 64 scopeid 0x20<link>
ether 00:50:b6:ca:bb:5b txqueuelen 1000 (Ethernet)
RX packets 46 bytes 2116 (2.0 KiB)
RX errors 0 dropped 0 overruns 0 frame 0
TX packets 13 bytes 2146 (2.0 KiB)
TX errors 0 dropped 0 overruns 0 carrier 0 collisions 0
lo: flags=73<UP,LOOPBACK,RUNNING> mtu 65536
inet 127.0.0.1 netmask 255.0.0.0
inet6 ::1 prefixlen 128 scopeid 0x10<host>
loop txqueuelen 1000 (Local Loopback)
RX packets 258 bytes 16182 (15.8 KiB)
RX errors 0 dropped 0 overruns 0 frame 0
TX packets 258 bytes 16182 (15.8 KiB)
TX errors 0 dropped 0 overruns 0 carrier 0 collisions 0
enp0s10
enp0s4f1u2Description='A basic static ethernet connection'
Interface=enp0s10
Connection=ethernet
IP=static
Address=('192.168.0.90/24')
Gateway=('192.168.0.254')
DNS=('192.168.0.254' '8.8.4.4')
Je ne comprends pas le problèmeDescription='USB ETHERNET Adaptator'
Interface=enp0s4flu2
Connection=ethernet
IP=static
Address=('192.168.2.90/24')
#Routes=('192.168.2.0/24 via 192.168.1.2')
Gateway='192.168.2.1'
DNS=('192.168.2.1' '8.8.4.4'))
Merci d'avance